document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=256448>Question 256448</A>: <I><SPAN STYLE=\"word-break: break-all;\"> inverse functions\r<BR>\n" );
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document.write( "find f(g(x)) and g(f(x)) and determine whether the functions f and g are inverse of each other.\r<BR>\n" );
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document.write( "f(x)= 6x-3 and g(x)= x+6/3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #188564 by </B><A HREF=/tutors/aboutme.mpl?userid=drk><B>drk(1908)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=drk><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=188564\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> F(g(x)) means put the g(x) function into the f(x) function. We get:<BR>\n" );
document.write( "f(g(x)) = 6(x+6/3) - 3 = 6x +12 - 3 = 6x + 9<BR>\n" );
document.write( "g(f(x)) = 6x-3 + 6/3 = 6x - 1<BR>\n" );
document.write( "The functions are not inverses </SPAN>\n" );
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