document.write( "Question 256421: Seven equally qualified students apply for a scholarship, but only five scholarships equal in value, can be given. How many ways can the five winners be selected? \n" ); document.write( "
Algebra.Com's Answer #188529 by Alan3354(69443)\"\" \"About 
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Seven equally qualified students apply for a scholarship, but only five scholarships equal in value, can be given. How many ways can the five winners be selected?
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\n" ); document.write( "The 1st selection is 1 of 7, then 1 of 6, then 1 of 5, etc
\n" ); document.write( "7*6*5*4*3 = 2520
\n" ); document.write( "But selecting A, B, C, D and E is the same as B, C, E, D and A. Person A has 5 chances to be selected. The 2nd has 4 chances to be selected, etc. 5*4*3*2*1 = 120.
\n" ); document.write( "The number of possible combinations is 2520/120 = 21
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\n" ); document.write( "To make it simpler, find the number of different ways 2 people are not selected:
\n" ); document.write( "The 1st is one of 7, the 2nd is one of 6 --> 7*6 = 42.
\n" ); document.write( "A and B is the same as B and A, so divide by 2
\n" ); document.write( "42/2 = 21.\r
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