document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=256411>Question 256411</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the graph of the parabola y2(squared)+6y+8x+25=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #188519 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=188519\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find the graph of the parabola y^2+6y+8x+25=0<BR>\n" );
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document.write( "Complete the square on the y-terms:<BR>\n" );
document.write( "y^2+6y+9 = -8x-25+9<BR>\n" );
document.write( "(y+3)^2 = -8x-16<BR>\n" );
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document.write( "solve for \"x\":<BR>\n" );
document.write( "8x = -(y+3)^2 - 16<BR>\n" );
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document.write( "x = (-1/8)(y+3)^2 - 2<BR>\n" );
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document.write( "Graph the parabola:<BR>\n" );
document.write( "Vertex at (-2,-3)<BR>\n" );
document.write( "Opens to the left.<BR>\n" );
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document.write( "If y = -3, x = -2<BR>\n" );
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document.write( "That is enough information to sketch the graph.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.  </SPAN>\n" );
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