document.write( "Question 32318: Bob and Moe set off at the same time on a 30km walk for charity. Bob who has trained all year for this event, walks 1.4km/h faster than Moe, but sees a friend en route and stops to talk for 20 min. Even with this delay, Bob finished the walk 2 hours ahead of Moe. How fast was each person walking, and how long did it take for each person to finish the walk? \n" ); document.write( "
Algebra.Com's Answer #18850 by Paul(988)\"\" \"About 
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Let the rate for Moe be x
\n" ); document.write( "Let the rate for Bob be 1.4+x
\n" ); document.write( "Bob's partial time = 2 hours and 20 minuts (1/3 hours) or 7/3 hours:
\n" ); document.write( "Equation:
\n" ); document.write( "\"30%2F%281.4%2Bx%29-30%2Fx=7%2F3\"--->Multiply the whole equation by 3 to remove the fraction:
\n" ); document.write( "\"90%2F%281.4%2Bx%29-90%2Fx=7\"
\n" ); document.write( "90[(1.4+x)-(x)]=7[(1.4+x)(x)]}}}
\n" ); document.write( "\"126=7%281.4x%2Bx%5E2%29\"
\n" ); document.write( "\"7x%5E2%2B9.8x-126=0\"
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "a=7, b=9.8, c=-126
\n" ); document.write( "
\n" ); document.write( "SImplfy:
\n" ); document.write( "x=3.6
\n" ); document.write( "3.6+1.4=5
\n" ); document.write( "Total time for each: -->30/(5)=6 and 30/3.6=8.33
\n" ); document.write( "Hence, Bob's rate is 5kmph with 6 hours of total, and Moe's rate is 3.6kmph with 8.33 hours of total.
\n" ); document.write( "
Paul.
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