document.write( "Question 32318: Bob and Moe set off at the same time on a 30km walk for charity. Bob who has trained all year for this event, walks 1.4km/h faster than Moe, but sees a friend en route and stops to talk for 20 min. Even with this delay, Bob finished the walk 2 hours ahead of Moe. How fast was each person walking, and how long did it take for each person to finish the walk? \n" ); document.write( "
Algebra.Com's Answer #18850 by Paul(988)![]() ![]() ![]() You can put this solution on YOUR website! Let the rate for Moe be x \n" ); document.write( "Let the rate for Bob be 1.4+x \n" ); document.write( "Bob's partial time = 2 hours and 20 minuts (1/3 hours) or 7/3 hours: \n" ); document.write( "Equation: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "90[(1.4+x)-(x)]=7[(1.4+x)(x)]}}} \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "a=7, b=9.8, c=-126 \n" ); document.write( " \n" ); document.write( "SImplfy: \n" ); document.write( "x=3.6 \n" ); document.write( "3.6+1.4=5 \n" ); document.write( "Total time for each: -->30/(5)=6 and 30/3.6=8.33 \n" ); document.write( "Hence, Bob's rate is 5kmph with 6 hours of total, and Moe's rate is 3.6kmph with 8.33 hours of total. \n" ); document.write( "Paul. \n" ); document.write( " |