document.write( "Question 256371: Paul’s Plumbing charges $55 to visit a job site plus $35 per hour for labor. Reliable Plumbing charges $75 to visit a job site plus $30 per hour for labor. For how many hours of labor would the total charge be the same for the two companies? \n" ); document.write( "
Algebra.Com's Answer #188491 by Theo(13342)![]() ![]() You can put this solution on YOUR website! let x = number of hours.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "55 + 35*x = 75 + 30*x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "subtract 30*x from both sides of the equation and subtract 55 from both sides of the equation to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "5*x = 20\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "divide both sides of the equation by 5 to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the total charge should be the same in 4 hours.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "55 + 35*4 = 55 + 140 = 195\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "75 + 30*4 = 75 + 120 = 195\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "4 hours is confirmed.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that's your answer.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "total charge will be the same for both companies when the number of hours for the job is equal to 4.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |