document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=256341>Question 256341</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use substitution to solve 4t^1/3 - 5t^1/6 + 1 = 0.\r<BR>\n" );
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document.write( "I first tried multiplying the exponent of 4t^1/3 by 3 to get 4t^3 and was wondering if that was correct, if not what is? If it is, where do I go from there, do I just repeat it by multiplying 6 to the other side and setting it all equal to -1?\r<BR>\n" );
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document.write( "Thanks. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #188470 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=188470\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> substituting x for t^(1/6)\r<BR>\n" );
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document.write( "4x^2 - 5x + 1 = 0\r<BR>\n" );
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document.write( "factoring ___ (4x - 1) (x - 1) = 0\r<BR>\n" );
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document.write( "4x - 1 = 0 ___ x = 1/4 ___ substituting ___ t^(1/6) = 1/4 ___ t = 4^(-6)\r<BR>\n" );
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document.write( "x - 1 = 0 ___ x = 1 ___ substituting ___ t^(1/6) = 1 ___ t = 1 </SPAN>\n" );
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