document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=256261>Question 256261</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the formula for solving this: \"If you draw 4 M&Ms from a bag containing 4 red, 4 yellow, 4 green, and 4 brown ones, what is the probability that you will get 1 of each color?\" It boggles my mind. Thanks in advance!<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #188434 by </B><A HREF=/tutors/aboutme.mpl?userid=Greenfinch><B>Greenfinch(383)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Greenfinch><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Greenfinch><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=188434\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1st pick p = 1 (your are going to get a sweet and it doesn't matter which colour)<BR>\n" );
document.write( "2nd pick p= 12/15 anything but 1st colour (of which 3 are left)<BR>\n" );
document.write( "3rd pick p = 8/14 two colours left out of 4<BR>\n" );
document.write( "4th p = 4/13<BR>\n" );
document.write( "So probability is = 1 x 12/15 x 8/14 x 4/13 = 64/(5 x 7 x 13)= 64/455 </SPAN>\n" );
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