document.write( "Question 256189: A bus traveling at an average rate of 30 miles per hour left the city at 10:00 am. A car left 2 hours later, following the bus at 45 miles per hour. How many hours until they are both the same distance from the city? \n" ); document.write( "
Algebra.Com's Answer #188405 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! d=rt \n" ); document.write( "d=30t for the bus. \n" ); document.write( "d=45(t-2) for the car. \n" ); document.write( "Set the distances equal. \n" ); document.write( "30t=45(t-2) \n" ); document.write( "30t=45t-90 \n" ); document.write( "30t-45t=-90 \n" ); document.write( "-15t=-90 \n" ); document.write( "t=-90/-15 \n" ); document.write( "t=6 hours after the bus leaves they will be the same distance from the city. \n" ); document.write( "Proof: \n" ); document.write( "30*6=45(6-2) \n" ); document.write( "180=45*4 \n" ); document.write( "180=180 miles from the city after 6 hours. \n" ); document.write( " |