document.write( "Question 4212: simplify:-
\n" ); document.write( "(log3 135)/(log15 3) - (log3 5)/(log405 3)
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Algebra.Com's Answer #1884 by longjonsilver(2297)\"\" \"About 
You can put this solution on YOUR website!
first change the base, so that all are base 3...i will not write the base anymore, to ease the readability:\r
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\n" ); document.write( "\n" ); document.write( "\"%28log135log15%29%2F%28log3%29+-+%28log5log405%29%2F%28log3%29\"\r
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\n" ); document.write( "\n" ); document.write( "Since log3 to base 3 is 1, we get \"log135log15+-+log5log405\"\r
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\n" ); document.write( "\n" ); document.write( "135 = 5*27
\n" ); document.write( "405 = 5*81
\n" ); document.write( "and 15 = 5*3, so we get:\r
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\n" ); document.write( "\n" ); document.write( "\"log%2827%2A5%29log%283%2A5%29+-+log5log%2881%2A5%29\"\r
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\n" ); document.write( "\n" ); document.write( "(log27+log5)(log3+log5) - log5(log81+log5)\r
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\n" ); document.write( "\n" ); document.write( "log27log3 + log27log5 + log3log5 + (log5)^2 - log81log5 - (log5)^2\r
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\n" ); document.write( "\n" ); document.write( "Now, log27 to base 3 is 3
\n" ); document.write( "and log81 to base 3 is 4, so...\r
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\n" ); document.write( "\n" ); document.write( "3log3 + 3log5 + log5 + (log5)^2 - 4log5 - (log5)^2\r
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\n" ); document.write( "\n" ); document.write( "everything cancels except for the 3, so this is the answer!\r
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\n" ); document.write( "\n" ); document.write( "jon
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