document.write( "Question 4212: simplify:-
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document.write( "(log3 135)/(log15 3) - (log3 5)/(log405 3) \n" );
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Algebra.Com's Answer #1884 by longjonsilver(2297)![]() ![]() You can put this solution on YOUR website! first change the base, so that all are base 3...i will not write the base anymore, to ease the readability:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since log3 to base 3 is 1, we get \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "135 = 5*27 \n" ); document.write( "405 = 5*81 \n" ); document.write( "and 15 = 5*3, so we get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(log27+log5)(log3+log5) - log5(log81+log5)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "log27log3 + log27log5 + log3log5 + (log5)^2 - log81log5 - (log5)^2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now, log27 to base 3 is 3 \n" ); document.write( "and log81 to base 3 is 4, so...\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3log3 + 3log5 + log5 + (log5)^2 - 4log5 - (log5)^2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "everything cancels except for the 3, so this is the answer!\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "jon \n" ); document.write( " \n" ); document.write( " |