document.write( "Question 256212: A rectangle parcel of land is 50ft wide. The length of a diagonal between opposite corners is 10ft more than the length of the parcel. What is the length of the parcel?\r
\n" );
document.write( "\n" );
document.write( "x= length in ft of the parcel
\n" );
document.write( "area = length x width\r
\n" );
document.write( "\n" );
document.write( "x^2 + 50^2 = (x + 100)^2
\n" );
document.write( "x^2 + 2500 = x^2 + 100 \n" );
document.write( "
Algebra.Com's Answer #188383 by scott8148(6628)![]() ![]() You can put this solution on YOUR website! x= length in ft of the parcel \n" ); document.write( "area = length x width ___ ??? \n" ); document.write( "x^2 + 50^2 = (x + 100)^2 ___ almost, but not quite ___ x^2 + 50^2 = (x + 10)^2 \n" ); document.write( "x^2 + 2500 = x^2 + 20x + 100\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2400 = 20x ___ 120 = x\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this is a 5, 12, 13 Pythagorean triple \n" ); document.write( " |