document.write( "Question 256212: A rectangle parcel of land is 50ft wide. The length of a diagonal between opposite corners is 10ft more than the length of the parcel. What is the length of the parcel?\r
\n" ); document.write( "\n" ); document.write( "x= length in ft of the parcel
\n" ); document.write( "area = length x width\r
\n" ); document.write( "\n" ); document.write( "x^2 + 50^2 = (x + 100)^2
\n" ); document.write( "x^2 + 2500 = x^2 + 100
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Algebra.Com's Answer #188380 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "I'm not sure why you introduced the idea of the area of the rectangle into this. You are dealing with a right triangle which has sides of 50 and and a hypotenuse of \r
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\n" ); document.write( "\n" ); document.write( "At that, you almost had it right. Using Pythagoras:\r
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\n" ); document.write( "\n" ); document.write( "I'm assuming that the first relationship you wrote just had a typo in it and that you meant what I just wrote above.\r
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\n" ); document.write( "\n" ); document.write( "Now here is where you really got off track. You tried to say that . No! No! No! 1000 times No!\r
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\n" ); document.write( "\n" ); document.write( "In general, (Remember FOIL?)\r
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\n" ); document.write( "\n" ); document.write( "So, your next step SHOULD have been:\r
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\n" ); document.write( "\n" ); document.write( "Which simplifies to:\r
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