document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=256168>Question 256168</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is long length of right triangle when a=20inches and b=48 inches<BR>\n" );
document.write( "then what is the length of c? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #188343 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=188343\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Garamond\" size=\"+2\">\r<BR>\n" );
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document.write( "Use Pythagoras to find the measure of the hypotenuse of a right triangle given the measures of the two legs.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ c\ =\ \sqrt{a^2\ +\ b^2}\">\r<BR>\n" );
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document.write( "For your problem:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ c\ =\ \sqrt{(20)^2\ +\ (48)^2}\">\r<BR>\n" );
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document.write( "The arithmetic, as usual, is yours to do.  Of course, you could also recognize that 20 is 5 times 4 and 48 is 12 times 4, and recall that 5, 12, and 13 is a Pythagorean Triple hence the hypotenuse of your triangle must be 13 times 4.\r<BR>\n" );
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document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi} + 1 = 0\"><BR>\n" );
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