document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=256038>Question 256038</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A factory manufacturing tennis balls determines that the probability that a single can of three balls will contain at least one defective ball is .025. what is the probability that a case of 48 cans will contain at least two cans with a defective ball? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #188329 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=188329\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let d=.025 and g=1-.025=.975<BR>\n" );
document.write( "We have to expand the binomial (g+d)^48<BR>\n" );
document.write( "g^48=.975^48=.2966 Prob of no defective cans<BR>\n" );
document.write( "48g^47d=48(.975)^47(.025)=48*.3042*.025=.3651 Prob one defective can.<BR>\n" );
document.write( "1-.2966-.3651=.3473 prob of at lest 2 cans with a defective ball.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
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