document.write( "Question 256137: Give triangele RST with vertices R(-2,1) S(-1,3) and T(2,1) RS equals ?\r
\n" ); document.write( "\n" ); document.write( "I think the square root of 5 but Im not sure if I approched it correectly.
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Algebra.Com's Answer #188310 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
We basically want to find the distance from R(-2,1) to S(-1,3)\r
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\n" ); document.write( "\n" ); document.write( "Note: is the first point . So this means that \"x%5B1%5D=-2\" and \"y%5B1%5D=1\".\r
\n" ); document.write( "\n" ); document.write( "Also, is the second point . So this means that \"x%5B2%5D=-1\" and \"y%5B2%5D=3\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%28x%5B1%5D-x%5B2%5D%29%5E2%2B%28y%5B1%5D-y%5B2%5D%29%5E2%29\" Start with the distance formula.\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%28-2--1%29%5E2%2B%281-3%29%5E2%29\" Plug in \"x%5B1%5D=-2\", \"x%5B2%5D=-1\", \"y%5B1%5D=1\", and \"y%5B2%5D=3\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%28-1%29%5E2%2B%281-3%29%5E2%29\" Subtract \"-1\" from \"-2\" to get \"-1\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%28-1%29%5E2%2B%28-2%29%5E2%29\" Subtract \"3\" from \"1\" to get \"-2\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%281%2B%28-2%29%5E2%29\" Square \"-1\" to get \"1\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%281%2B4%29\" Square \"-2\" to get \"4\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%285%29\" Add \"1\" to \"4\" to get \"5\".\r
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\n" ); document.write( "\n" ); document.write( "So our answer is \"d=sqrt%285%29\" which means that the length of RS is \"sqrt%285%29\" units.
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