document.write( "Question 256134: $\"x%5E2=x%2B12\"$ \n" ); document.write( "

Algebra.Com's Answer #188292 by drk(1908) $\"\"$ $\"About$

You can put this solution on YOUR website!
Here is the original question:
\n" ); document.write( "(i) $\"x%5E2=x%2B12\"$
\n" ); document.write( "step 1 - move everything over to 1 side so it is = 0 we get
\n" ); document.write( "(ii) $\"x%5E2+-+x+-+12+=+0\"$
\n" ); document.write( "step 2 - factor the left side to get
\n" ); document.write( "(iii) $\"%28x-4%29%28x%2B3%29+=+0\"$
\n" ); document.write( "step 3 - solve each parenthesis for x and we get
\n" ); document.write( "x-4 = 0
\n" ); document.write( "x = 4
\n" ); document.write( "x+3=0
\n" ); document.write( "x=-3 \n" ); document.write( "

\n" );