document.write( "Question 255923: the sum of two numbers is 13. two times the first number minus three times the second number is 1. if you let x stand for the first number and y for the second number, what are the two numbers \n" ); document.write( "
Algebra.Com's Answer #188289 by EMStelley(208)\"\" \"About 
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If our two numbers are x and y, to do this problem we just take it one sentence at a time.\r
\n" ); document.write( "\n" ); document.write( "\"the sum of two numbers is 13\"
\n" ); document.write( "This tells us that when you add our two numbers you get 13. So we have:
\n" ); document.write( "x+y=13\r
\n" ); document.write( "\n" ); document.write( "\"two times the first number minus three times the second number is 1\"
\n" ); document.write( "Two times the first number would be represented by 2x and three times the second number is represented by 3y. So we have:
\n" ); document.write( "2x-3y=1\r
\n" ); document.write( "\n" ); document.write( "So we have a system of equations:
\n" ); document.write( "\"x%2By=13\"
\n" ); document.write( "\"2x-3y=1\"\r
\n" ); document.write( "\n" ); document.write( "Let's use the addition method to solve this system. If we multiply the first equation by 3 we will be able to eliminate the y's.\r
\n" ); document.write( "\n" ); document.write( "\"3x%2B3y=39\"
\n" ); document.write( "\"2x-3y=1\"\r
\n" ); document.write( "\n" ); document.write( "Now we add:\r
\n" ); document.write( "\n" ); document.write( "\"5x=40\"
\n" ); document.write( "\"x=8\"\r
\n" ); document.write( "\n" ); document.write( "And using our first equation we have that y must be 5. So our two numbers are 8 and 5.
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