document.write( "Question 256066: -6y=-18-6x
\n" ); document.write( "6x-5y=-12
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Algebra.Com's Answer #188284 by EMStelley(208)\"\" \"About 
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\"-6y=-18-6x\"
\n" ); document.write( "\"6x-5y=-12\"\r
\n" ); document.write( "\n" ); document.write( "When solving a system of equations, you can either solve by substitution or adding. Most students prefer adding, so I will go with that method. The first step is to get both of the equations in the same form. I will do this by adding 6x to both sides in the first equation:\r
\n" ); document.write( "\n" ); document.write( "\"6x-6y=-18\"
\n" ); document.write( "\"6x-5y=-12\"\r
\n" ); document.write( "\n" ); document.write( "Next, we need to manipulate one or both of the equations in order to be able to get rid of a variable when adding. Notice that if we multiply the first equation by -1, the x's will be removed when added.\r
\n" ); document.write( "\n" ); document.write( "\"-6x%2B6y=18\"
\n" ); document.write( "\"6x-5y=-12\"\r
\n" ); document.write( "\n" ); document.write( "Now we add down the columns and obtain:\r
\n" ); document.write( "\n" ); document.write( "\"y=6\"\r
\n" ); document.write( "\n" ); document.write( "Now that we have found y, we substitute it back into one of the original equations in order to find x. I will use the second equation (it doesn't matter which one you use).\r
\n" ); document.write( "\n" ); document.write( "\"6x-5%286%29=-12\"
\n" ); document.write( "\"6x-30=-12\"
\n" ); document.write( "\"6x=18\"
\n" ); document.write( "\"x=3\"\r
\n" ); document.write( "\n" ); document.write( "Thus the answer is (3,6).
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