document.write( "Question 32214: The intensity of light X, measured in foot-candles, varies inversely as the square of the distance from the light d. If X=4/5 foot-candles when the distance is 20 feet. Find the constant of varieation and then find the intensity when the distance is 16 feet.\r
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Algebra.Com's Answer #18828 by venugopalramana(3286)\"\" \"About 
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The intensity of light X, measured in foot-candles, varies inversely as the square of the distance from the light d. If X=4/5 foot-candles when the distance is 20 feet. Find the constant of varieation and then find the intensity when the distance is 16 feet.
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\n" ); document.write( "The intensity of light X, measured in foot-candles, varies inversely as the square of the distance from the light d. HENCE...
\n" ); document.write( "INTENSITY = X =K/D^2...WHERE K IS A CONSTNT AND D IS THE DISTANCE FROM LIGHT SOURCE.
\n" ); document.write( "If X=4/5 foot-candles when the distance is 20 feet.
\n" ); document.write( "4/5=K/20*20...K=20*20*4/5=320
\n" ); document.write( "Find the constant of varieation
\n" ); document.write( "K=320
\n" ); document.write( " and then find the intensity when the distance is 16 feet.
\n" ); document.write( "X=320/16*16=5/4 FOOT CANDLES.
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