document.write( "Question 256102: 4(2^x)+31(2^x)-8=0 \n" ); document.write( "
Algebra.Com's Answer #188262 by jim_thompson5910(35256)\"\" \"About 
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\"4%282%5Ex%29%2B31%282%5Ex%29-8=0\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "Let \"z=2%5Ex\"\r
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\n" ); document.write( "\n" ); document.write( "\"4z%2B31z-8=0\" Replace each \"2%5Ex\" term with 'z'\r
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\n" ); document.write( "\n" ); document.write( "\"35z-8=0\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"35z=8\" Add 8 to both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"z=8%2F35\" Divide both sides by 35.\r
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\n" ); document.write( "\n" ); document.write( "\"2%5Ex=8%2F35\" Plug in \"z=2%5Ex\"\r
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\n" ); document.write( "\n" ); document.write( "Recall that \"b%5Ex=y\" can be rewritten as \"log%28b%2C%28y%29%29=x\"\r
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\n" ); document.write( "\n" ); document.write( "\"log%282%2C%288%2F35%29%29=x\" Use the property shown above to rewrite the equation.\r
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\n" ); document.write( "\n" ); document.write( "\"x=log%282%2C%288%2F35%29%29\" Rearrange the equation.\r
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\n" ); document.write( "\n" ); document.write( "So the exact answer is \"x=log%282%2C%288%2F35%29%29\" which approximates to \"x=-2.12928\"
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