document.write( "Question 256025: An integer from 100 through 999, inclusive, is to be chosen at random. What is the probability that the number chosen will have 0 as at least 1 digit?\r
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document.write( "a) 19/900 b) 81/900 c) 90/900 d) 171/900 e) 271/900 \n" );
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Algebra.Com's Answer #188168 by drk(1908)![]() ![]() ![]() You can put this solution on YOUR website! FIrst we have to find the total number of integers in the set: 999-100+1 = 900. \n" ); document.write( "Next we need an organized way to determine our successful options: 0 in at least 1 digit. \n" ); document.write( "0 in 3 digits: \n" ); document.write( "0 \n" ); document.write( "0 in 2 digits: \n" ); document.write( "100, 200, 300, 400, 500, 600, 700, 800, 900 = 9 \n" ); document.write( "0 in 1 digit: \n" ); document.write( "101 - 110, 120, 130, 140, . . ., 190: 18 \n" ); document.write( "201 - 210, 220, 230, 240, . . ., 290: 18 \n" ); document.write( ". . . \n" ); document.write( "901-910, 920, 930, 940, . . . 990: 18 \n" ); document.write( "or 18*9 = 162 \n" ); document.write( "Now 0 +9 + 162 = 171 \n" ); document.write( "So the probability is \n" ); document.write( "171/900 = 19/100 \n" ); document.write( " |