document.write( "Question 256025: An integer from 100 through 999, inclusive, is to be chosen at random. What is the probability that the number chosen will have 0 as at least 1 digit?\r
\n" ); document.write( "\n" ); document.write( "a) 19/900 b) 81/900 c) 90/900 d) 171/900 e) 271/900
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Algebra.Com's Answer #188168 by drk(1908)\"\" \"About 
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FIrst we have to find the total number of integers in the set: 999-100+1 = 900.
\n" ); document.write( "Next we need an organized way to determine our successful options: 0 in at least 1 digit.
\n" ); document.write( "0 in 3 digits:
\n" ); document.write( "0
\n" ); document.write( "0 in 2 digits:
\n" ); document.write( "100, 200, 300, 400, 500, 600, 700, 800, 900 = 9
\n" ); document.write( "0 in 1 digit:
\n" ); document.write( "101 - 110, 120, 130, 140, . . ., 190: 18
\n" ); document.write( "201 - 210, 220, 230, 240, . . ., 290: 18
\n" ); document.write( ". . .
\n" ); document.write( "901-910, 920, 930, 940, . . . 990: 18
\n" ); document.write( "or 18*9 = 162
\n" ); document.write( "Now 0 +9 + 162 = 171
\n" ); document.write( "So the probability is
\n" ); document.write( "171/900 = 19/100
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