document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=256007>Question 256007</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how much water must be added to 50 gallons of a 40% alcohol solution to reduce the concentration to 16% alcohol? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #188164 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=188164\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=amount of water that needs to be added<BR>\n" );
document.write( "Now we know that the amount of pure alcohol before the water is added(0.40*50) has to equal the amount of pure alcohol after the water is added(0.16(50+x)).  So our equation to solve is:<BR>\n" );
document.write( "0.40*50=0.16(50+x)  get rid of parens and simplify<BR>\n" );
document.write( "20=8+0.16x  subtract 8 from each side<BR>\n" );
document.write( "20-8=8-8+0.16x or<BR>\n" );
document.write( "12=0.16x  divide each side by 0.16<BR>\n" );
document.write( "x=75 gal ---amount of water that needs to be added\r<BR>\n" );
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document.write( "CK<BR>\n" );
document.write( "0.40*50=0.16*(50+75)<BR>\n" );
document.write( "20=0.16*125<BR>\n" );
document.write( "20=20\r<BR>\n" );
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document.write( "Hope this helps----ptaylor </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );