document.write( "Question 32196: The section that I am on in my class is over contradiction. The equation is Show that neither x=1 or x=-1 can be solutions to the equation ax^2+bx+a=0 where a and b are integers with b odd. \n" ); document.write( "
Algebra.Com's Answer #18816 by mbarugel(146)![]() ![]() ![]() You can put this solution on YOUR website! Hello! \n" ); document.write( "Try plugging x = 1 into the equation. You get:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "However, b is odd, but 2a is even (two multiplied by any number yields an even number). Therefore, x=1 can't be a solution to the equation.\r \n" ); document.write( "\n" ); document.write( "When plugging x = -1, we get:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Using the same reasoning, we conclude that x=-1 can't be a solution of your equation.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I hope this helps! \n" ); document.write( "Get more answers at Online Math Answers.com! \n" ); document.write( " \n" ); document.write( " |