document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=255995>Question 255995</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A father is 6 times as old as his son and 3 times as old as his daughter. If the daughter is 5 years older than the son ,how old is each? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #188158 by </B><A HREF=/tutors/aboutme.mpl?userid=palanisamy><B>palanisamy(496)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=palanisamy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=188158\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  Let the age of the son = x<BR>\n" );
document.write( "Then the age of the daughter = x+5<BR>\n" );
document.write( "Given,A father is 6 times as old as his son and 3 times as old as his daughter.<BR>\n" );
document.write( "           6x = 3(x+5)<BR>\n" );
document.write( "           6x = 3x+15<BR>\n" );
document.write( "        6x-3x = 15<BR>\n" );
document.write( "           3x = 15<BR>\n" );
document.write( "            x = 15/3<BR>\n" );
document.write( "            x = 5<BR>\n" );
document.write( "Therefore,the age of the son = 5 years<BR>\n" );
document.write( "The age of the daughter = x+5 = 5+5 = 10 years<BR>\n" );
document.write( "the age of the son = x<BR>\n" );
document.write( "The age of the father = 6x = 6*5 = 30 years\r<BR>\n" );
document.write( "\n" );
document.write( "     </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );