document.write( "Question 255865: solve:
\n" ); document.write( "The sum of the squares of two consecutive negative even integers is 100.
\n" ); document.write( "Find the integers. \n" ); document.write( "

Algebra.Com's Answer #188097 by unlockmath(1688) $\"\"$ $\"About$

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Hello,
\n" ); document.write( "Let's set up -x will represent a negative integer and -x+2 will represent the next negative integer. Now we can set up our equation as:
\n" ); document.write( "(-x)^2 + (-x+2)^2=100 Rewrite this as:
\n" ); document.write( "x^2+x^2-4x+4=100 Subtract 100 from both sides to be:
\n" ); document.write( "x^2+x^2-4x-96=0 Combine like terms will result in:
\n" ); document.write( "2x^2-4x-96 Factor out a 2 will be:
\n" ); document.write( "2(x^2-2x-48)=0 This can be fractored as:
\n" ); document.write( "2(x-8)(x+6)=0 Now we know that:
\n" ); document.write( "x=8
\n" ); document.write( "x=-6
\n" ); document.write( "8 works as the answer so the negative integers are -8 and -6.
\n" ); document.write( "Square both of those and you'll see it adds up to 100.
\n" ); document.write( "Make sense?
\n" ); document.write( "RJ
\n" ); document.write( "Check out a new math book at:
\n" ); document.write( "www.math-unlock.com \n" ); document.write( "

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