document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=255837>Question 255837</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangle is 6cm long and 5 cm wide. When each dimension is increased by x cm, the area is tripled. Find the value of x.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #188071 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=188071\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  A rectangle is 6cm long and 5 cm wide. When each dimension is increased by x cm, the area is tripled. Find the value of x. <BR>\n" );
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document.write( "Original area = 6*5  = 30 cm^2<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "(6+x)(5+x) = 3*30<BR>\n" );
document.write( "x^2 + 11x + 30 - 90 = 0<BR>\n" );
document.write( "x^2 + 11x - 60 = 0<BR>\n" );
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document.write( "(x+15)(x-4) = 0 <BR>\n" );
document.write( "Positive solution:<BR>\n" );
document.write( "x = 4 cm<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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