document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=255749>Question 255749</A>: <I><SPAN STYLE=\"word-break: break-all;\"> When a number is diminished by its opposite, the result is 12. Find the number.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #188013 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=188013\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Your first problem is a fun trick.<BR>\n" );
document.write( "A number added to its opposite is 0.<BR>\n" );
document.write( "6+(-6)=0<BR>\n" );
document.write( "So if you are diminishing  by its opposite you are doubling it.<BR>\n" );
document.write( "6-(-6)=12<BR>\n" );
document.write( "Sorry but you are limited by the website rules to one question per submission and limited to 4 problems daily and also no similar problems.<BR>\n" );
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