document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=255743>Question 255743</A>: <I><SPAN STYLE=\"word-break: break-all;\"> It takes George 1 hour longer to mow the lawn than it takes Henry. Working together, using two mowers, they can mow the lawn in 1 hour and 12 minutes. How long would it take Henry to mow the lawn by himself? \r<BR>\n" );
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document.write( "Thank you!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #188006 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=188006\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x=y+1<BR>\n" );
document.write( "xy/(x+y)=1.2<BR>\n" );
document.write( "Substitute (y+1) for x & solve for y<BR>\n" );
document.write( "(y+1)y/(y+1+y)=1.2<BR>\n" );
document.write( "(y^2+y)/(2y+1)=1.2 cross multiply.<BR>\n" );
document.write( "y^2+y=1.2(2y+1)<BR>\n" );
document.write( "y^2+y=2.4y+1.2<BR>\n" );
document.write( "y^2+y-2.4y-1.2=0<BR>\n" );
document.write( "y^2-1.4y-1.2=0<BR>\n" );
document.write( "(y-2)(y+.6)=0<BR>\n" );
document.write( "y-2=0<BR>\n" );
document.write( "y=2 hours for Henry.<BR>\n" );
document.write( "x=2+1=3 hours for George.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "2*3/(2+3)=1.2<BR>\n" );
document.write( "6/5=1.2<BR>\n" );
document.write( "1.2=1.2  </SPAN>\n" );
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