document.write( "Question 255744: The sum of the squares of two positive consecutive integers is 41. Find integers. Show steps please^^ \n" ); document.write( "
Algebra.Com's Answer #188002 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
x & x+1 are the 2 consecutive numbers.
\n" ); document.write( "x^2+(x+1)=41
\n" ); document.write( "x^2+x^2+2x+1=41
\n" ); document.write( "2x^2+2x+1-41=0
\n" ); document.write( "2x^2+2x-40=0
\n" ); document.write( "2(x^2+x-20)=0
\n" ); document.write( "2(x+5)(x-4)=0
\n" ); document.write( "x-4=0
\n" ); document.write( "x=4 ans.
\n" ); document.write( "4+1=5 ans.
\n" ); document.write( "Proof:
\n" ); document.write( "4^2+5^2=41
\n" ); document.write( "16+25=41
\n" ); document.write( "41=41
\n" ); document.write( "
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