document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=255487>Question 255487</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How much of a 50% acid solution must be mixed with 8 gallons of a 22% acid solution to obtain a solution that is 40% acid? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #188000 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=188000\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .50x+.22*8=.40(8+x)<BR>\n" );
document.write( ".50x+1.76=3.2+.40x<BR>\n" );
document.write( ".50x-.40x=3.2-1.76<BR>\n" );
document.write( ".1x=1.44<BR>\n" );
document.write( "x=1.44/.1<BR>\n" );
document.write( "x=14.4 gals. of 50% acid is used.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( ".50*14.4+.22*8=.40(8+14.4)<BR>\n" );
document.write( "7.2+1.76=.40*22.4<BR>\n" );
document.write( "8.96=8.96<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );