document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=255567>Question 255567</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a car leaves a train station traveling west at a speed of 40 kilometers per hour. a train leaves the station three hours later traveling west at a rate of 120 kilometers per hour. in how many hours will the train catch up to the car? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #187992 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=187992\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> d=rt<BR>\n" );
document.write( "Because the distances are the same we have:<BR>\n" );
document.write( "40t=120(t-3)<BR>\n" );
document.write( "40t=120t-360<BR>\n" );
document.write( "40t-120t=-360<BR>\n" );
document.write( "-80t=360<BR>\n" );
document.write( "t=-360/-80<BR>\n" );
document.write( "t=4.5 hours after the car leaves the station they will meet.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "40*4.5=120(4.5-3)<BR>\n" );
document.write( "180=120*1.5<BR>\n" );
document.write( "180=180 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );