document.write( "Question 255290: Hi.Troy and Phil agree to meet at the movies.Phil drives 24 miles while troy rides his bike the 5 miles from his house at a speed of 15 miles per hour.If troy left 15 minutes later than Phil and they arrived at the theater at the same time, how fast did phil drive? \n" ); document.write( "
Algebra.Com's Answer #187987 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! .Troy and Phil agree to meet at the movies.Phil drives 24 miles while troy rides his bike the 5 miles from his house at a speed of 15 miles per hour. \n" ); document.write( "If troy left 15 minutes later than Phil and they arrived at the theater at the same time, how fast did phil drive? \n" ); document.write( ": \n" ); document.write( "Let s = Phil's speed \n" ); document.write( "Change 15 min to 1/4 hr \n" ); document.write( ": \n" ); document.write( "Write a time equation; Time = dist/speed \n" ); document.write( ": \n" ); document.write( "P's time = T's time + 15 min \n" ); document.write( " \n" ); document.write( "Multiply equation by 60s, results \n" ); document.write( "60(24) = 4s(5) + 15s \n" ); document.write( ": \n" ); document.write( "1440 = 20s + 15s \n" ); document.write( ": \n" ); document.write( "1440 = 35s \n" ); document.write( "s = \n" ); document.write( "s = 41.14 mph is Phil's speed \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution by finding the travel time of each \n" ); document.write( "24/41.14 = .583 hr \n" ); document.write( "15/5 = .333 hr \n" ); document.write( "-------------- \n" ); document.write( "difference .25 hr (15 min) \n" ); document.write( " |