document.write( "Question 255524: log[x]=log(x+1)+1 \n" ); document.write( "
Algebra.Com's Answer #187966 by EMStelley(208) You can put this solution on YOUR website! \n" ); document.write( "\n" ); document.write( "The problem here is that we have two logarithms. Our first step is too subtract log(x+1) from both sides.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now, using one of the laws of logarithms (log(a) - log(b) = log(a/b)) we have:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now we rewrite the problem in exponential form as:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now multiply both sides by x+1 :\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "However, you cannot take the log of a negative number. Thus, this equation has no solution. \n" ); document.write( " |