document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=255708>Question 255708</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The mean of the times it takes a commuter to get to work in Baltimore is 29.7 minutes. If the standard deviation is 6 minutes, within what liits would you expect approximately 68% of the times to fall? Assume the distribution is approximately bell-shaped. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #187959 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=187959\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The mean of the times it takes a commuter to get to work in Baltimore is 29.7 minutes. If the standard deviation is 6 minutes, within what liits would you expect approximately 68% of the times to fall? Assume the distribution is approximately bell-shaped.<BR>\n" );
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document.write( "68% of the times are within one standard deviation of the mean time.<BR>\n" );
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document.write( "mean-std = 29.7-6 = 23.7 minutes<BR>\n" );
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document.write( "mean+std = 29.7+6 = 35.7 minutes<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.  </SPAN>\n" );
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