document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=255703>Question 255703</A>: <I><SPAN STYLE=\"word-break: break-all;\"> trains A and B are traveling in the same direction on the parallel tracks. train A is traveling 100 miles per hour and train B is traveling at 110miles per hour. Train A passed a station at 7:10pm if train B passes the same station at 7:22pm. At what time till train B catch up with train A?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #187954 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=187954\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  trains A and B are traveling in the same direction on the parallel tracks. train A is traveling 100 miles per hour and train B is traveling at 110miles per hour. Train A passed a station at 7:10pm if train B passes the same station at 7:22pm. At what time till train B catch up with train A?<BR>\n" );
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document.write( "722 - 710 = 12 minutes = 1/5 hour<BR>\n" );
document.write( "Train A goes 20 miles in that time (100 mph * 1/5 hour) and it 20 miles ahead of train B at 722.<BR>\n" );
document.write( "Train B is gaining on train A at 10 mph (110 - 100).<BR>\n" );
document.write( "20 miles/10 mph = 2 hours.<BR>\n" );
document.write( "722 + 200 = 922 PM\r<BR>\n" );
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