document.write( "Question 255703: trains A and B are traveling in the same direction on the parallel tracks. train A is traveling 100 miles per hour and train B is traveling at 110miles per hour. Train A passed a station at 7:10pm if train B passes the same station at 7:22pm. At what time till train B catch up with train A?
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Algebra.Com's Answer #187953 by stanbon(75887) ![]() You can put this solution on YOUR website! trains A and B are traveling in the same direction on the parallel tracks. train A is traveling 100 miles per hour and train B is traveling at 110miles per hour. Train A passed a station at 7:10pm if train B passes the same station at 7:22pm. At what time till train B catch up with train A? \n" ); document.write( "------------- \n" ); document.write( "Train A DATA: \n" ); document.write( "rate = 100 mph ; time = x hrs. ; distance = rt = 100x miles \n" ); document.write( "----- \n" ); document.write( "Train B DATA: \n" ); document.write( "rate = 110 mph ; time = (x-(22/60)) hrs ; distance = 110*(x-(11/30)) miles \n" ); document.write( "-------------------------- \n" ); document.write( "Equation: \n" ); document.write( "distance = distance \n" ); document.write( "100x = 110(30x-11)/30) \n" ); document.write( "(10/11)x = (30x-11)/30 \n" ); document.write( "Cross-multiply: \n" ); document.write( "300x = 11(30x-11) \n" ); document.write( "300x = 330x - 121 \n" ); document.write( "30x = 121 \n" ); document.write( "x = 121/30 hr (time for A Train) \n" ); document.write( "---- \n" ); document.write( "Time = 7:10 + (121/30) hr \n" ); document.write( "Time = 7:10 + 4 hrs + 0.033333*60 min \n" ); document.write( "Time = 11:10 + 2 minutes \n" ); document.write( "Time = 11:12 pm \n" ); document.write( "====================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |