document.write( "Question 255553: solve: sqrt of x+5 + sqrt of x-3 = 4 \n" ); document.write( "
Algebra.Com's Answer #187920 by EMStelley(208)\"\" \"About 
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\"sqrt%28x%2B5%29+%2B+sqrt%28x-3%29+=+4\"\r
\n" ); document.write( "\n" ); document.write( "When you are solving a problem with two square roots, you always want to start by rearranging the formula to have one square root on each side:\r
\n" ); document.write( "\n" ); document.write( "\"sqrt%28x%2B5%29+=+4+-+sqrt%28x-3%29\"\r
\n" ); document.write( "\n" ); document.write( "Now we square both sides:\r
\n" ); document.write( "\n" ); document.write( "\"%28sqrt%28x%2B5%29%29%5E2+=+%284+-+sqrt%28x-3%29%29%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"x%2B5+=+%284-sqrt%28x-3%29%29%284-sqrt%28x-3%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"x%2B5+=+16+-+8sqrt%28x-3%29+%2B+x+-+3\"\r
\n" ); document.write( "\n" ); document.write( "Now, we combine like terms and isolate the one remaining square root:\r
\n" ); document.write( "\n" ); document.write( "\"x%2B5+=+x%2B13-8sqrt%28x-3%29\"\r
\n" ); document.write( "\n" ); document.write( "\"-8+=+-8sqrt%28x-3%29\"\r
\n" ); document.write( "\n" ); document.write( "\"1+=+sqrt%28x-3%29\"\r
\n" ); document.write( "\n" ); document.write( "And now we square both sides again:\r
\n" ); document.write( "\n" ); document.write( "\"1+=+x-3\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+4\"\r
\n" ); document.write( "\n" ); document.write( "The last step is to check our answer:\r
\n" ); document.write( "\n" ); document.write( "\"sqrt%284%2B5%29+%2B+sqrt%284-3%29+=+4\"
\n" ); document.write( "\"3+%2B+1+=+4\"\r
\n" ); document.write( "\n" ); document.write( "So x=4 is a valid solution.
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