document.write( "Question 255679: how do i do the 45 45 90 and the 30 60 90 triangles \n" ); document.write( "
Algebra.Com's Answer #187914 by CharlesG2(834)\"\" \"About 
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how do i do the 45 45 90 and the 30 60 90 triangles?\r
\n" ); document.write( "\n" ); document.write( "pythagorean theorem is for right triangle
\n" ); document.write( "(triangles with a 90 degree angle as one of the 3 angles)\r
\n" ); document.write( "\n" ); document.write( "a^2+b^2=c^2 where a and b are 2 of the sides and c is the diagonal (longest side) otherwise known as the hypotenuse\r
\n" ); document.write( "\n" ); document.write( "45 45 90
\n" ); document.write( "take a rectangle and slice it in two at the diagonal and take one of the halves,
\n" ); document.write( "that is this triangle\r
\n" ); document.write( "\n" ); document.write( "length ^2 + width ^2 = diagonal ^ 2\r
\n" ); document.write( "\n" ); document.write( "30 60 90
\n" ); document.write( "that is half of an equalateral triangle (a triangle with 3 equal sides)\r
\n" ); document.write( "\n" ); document.write( "the short side will be half the base and will be opposite the 30 degree angle
\n" ); document.write( "the height will be opposite the 60 degree angle
\n" ); document.write( "the hypotenuse will be opposite the 90 degree angle\r
\n" ); document.write( "\n" ); document.write( "(1/2 base)^2 + height ^2 = hypotenuse ^2\r
\n" ); document.write( "\n" ); document.write( "you can also use these ratios to come up with the sides if you know the angle
\n" ); document.write( "sine
\n" ); document.write( " opp/hyp
\n" ); document.write( "cosine
\n" ); document.write( " adj/hyp
\n" ); document.write( "tangent
\n" ); document.write( " opp/adj\r
\n" ); document.write( "\n" ); document.write( "the hypotenuse will always be opposite to the 90 degree angle\r
\n" ); document.write( "\n" ); document.write( "these are some of the ratios for these triangles
\n" ); document.write( "sine 45 = sqrt(2)/2
\n" ); document.write( "sine 90 = 1
\n" ); document.write( "sine 30 = 0.5
\n" ); document.write( "sine 60 = sqrt(3)/2
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