document.write( "Question 255679: how do i do the 45 45 90 and the 30 60 90 triangles \n" ); document.write( "
Algebra.Com's Answer #187914 by CharlesG2(834)![]() ![]() ![]() You can put this solution on YOUR website! how do i do the 45 45 90 and the 30 60 90 triangles?\r \n" ); document.write( "\n" ); document.write( "pythagorean theorem is for right triangle \n" ); document.write( "(triangles with a 90 degree angle as one of the 3 angles)\r \n" ); document.write( "\n" ); document.write( "a^2+b^2=c^2 where a and b are 2 of the sides and c is the diagonal (longest side) otherwise known as the hypotenuse\r \n" ); document.write( "\n" ); document.write( "45 45 90 \n" ); document.write( "take a rectangle and slice it in two at the diagonal and take one of the halves, \n" ); document.write( "that is this triangle\r \n" ); document.write( "\n" ); document.write( "length ^2 + width ^2 = diagonal ^ 2\r \n" ); document.write( "\n" ); document.write( "30 60 90 \n" ); document.write( "that is half of an equalateral triangle (a triangle with 3 equal sides)\r \n" ); document.write( "\n" ); document.write( "the short side will be half the base and will be opposite the 30 degree angle \n" ); document.write( "the height will be opposite the 60 degree angle \n" ); document.write( "the hypotenuse will be opposite the 90 degree angle\r \n" ); document.write( "\n" ); document.write( "(1/2 base)^2 + height ^2 = hypotenuse ^2\r \n" ); document.write( "\n" ); document.write( "you can also use these ratios to come up with the sides if you know the angle \n" ); document.write( "sine \n" ); document.write( " opp/hyp \n" ); document.write( "cosine \n" ); document.write( " adj/hyp \n" ); document.write( "tangent \n" ); document.write( " opp/adj\r \n" ); document.write( "\n" ); document.write( "the hypotenuse will always be opposite to the 90 degree angle\r \n" ); document.write( "\n" ); document.write( "these are some of the ratios for these triangles \n" ); document.write( "sine 45 = sqrt(2)/2 \n" ); document.write( "sine 90 = 1 \n" ); document.write( "sine 30 = 0.5 \n" ); document.write( "sine 60 = sqrt(3)/2 \n" ); document.write( " \n" ); document.write( " |