document.write( "Question 255665: 0.9=log(0.2-x/x) \n" ); document.write( "
Algebra.Com's Answer #187897 by CharlesG2(834)\"\" \"About 
You can put this solution on YOUR website!
0.9=log(0.2-x/x)\r
\n" ); document.write( "\n" ); document.write( "not sure if this is 0.9=log10 (0.2 - (x/x))
\n" ); document.write( "or 0.9=log10 ((0.2-x)/x)\r
\n" ); document.write( "\n" ); document.write( "0.9=log10 (0.2-(x/x))
\n" ); document.write( "0.9=log10 (0.2-1)
\n" ); document.write( "0.9=log10 (-0.8)
\n" ); document.write( "can not take log10 of a negative number\r
\n" ); document.write( "\n" ); document.write( "0.9=log10 ((0.2-x)/x)
\n" ); document.write( "0.9=log10 (y)\r
\n" ); document.write( "\n" ); document.write( "y = b^x <==> logb(y) = x
\n" ); document.write( "10^0.9=y\r
\n" ); document.write( "\n" ); document.write( "10^0.9=(0.2-x)/x
\n" ); document.write( "(10^0.9)x=0.2-x
\n" ); document.write( "(10^0.9)x+x=0.2
\n" ); document.write( "((10^0.9)+1)x=0.2
\n" ); document.write( "(7.943282+1)x=0.2
\n" ); document.write( "(8.943282)x=0.2
\n" ); document.write( "x=0.022363
\n" ); document.write( "
\n" );