document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=32253>Question 32253</A>: <I><SPAN STYLE=\"word-break: break-all;\"> need to solve for an \"X\" exponent:      2 (x power) = 1/4\r<BR>\n" );
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document.write( "I know the answer but dont know how to show it by solving it algebracially </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #18789 by </B><A HREF=/tutors/aboutme.mpl?userid=ikdeep><B>ikdeep(226)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ikdeep><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ikdeep><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=18789\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2 (x power) = 1/4\r<BR>\n" );
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document.write( "2^x = (1/2)^2.........here ^2 and ^x means power \r<BR>\n" );
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document.write( "now, take reciprocal or RHS ,,,,and you would know that when we take reciprocal,,the sign of its power changes ,,,so here we get...\r<BR>\n" );
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document.write( "2^x = (2)^-2\r<BR>\n" );
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document.write( "as the bases are same so they would be eliminated and we get......\r<BR>\n" );
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document.write( "x = -2\r<BR>\n" );
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document.write( "Now if you want to verify you answer ,,,you can put the values of x in the given equation and if you get LHS = RHS,,,this means that you answer is correct..\r<BR>\n" );
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document.write( "Hope this will help you \r<BR>\n" );
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document.write( "Please feel free to revert back for any further queries.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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