document.write( "Question 255655: log(x+2)=log x+2 \n" ); document.write( "

Algebra.Com's Answer #187884 by stanbon(75887) $\"\"$ $\"About$

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log(x+2)=log(x)+ 2
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\n" ); document.write( "log(x+2) - log(x) = 2
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\n" ); document.write( "log[(x+2)/x] = 2
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\n" ); document.write( "(x+2)/x = 10^2
\n" ); document.write( "x+2 = 100x
\n" ); document.write( "99x = 2
\n" ); document.write( "x = 2/99
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "

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