document.write( "Question 255619: A triangle with a perimeter of 20cm. Two angles are 30 and 50. What are the lengths of the sides in cm. \n" ); document.write( "
Algebra.Com's Answer #187848 by Edwin McCravy(20055)\"\" \"About 
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A triangle with a perimeter of 20cm. Two angles are 30 and 50. What are the lengths of the sides in cm.
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document.write( "Since the sum of the three angles of any triangle is 180°, we\r\n" );
document.write( "have that the third angle is 180° - (30°+50°) = 180° - 80° = 100° \r\n" );
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document.write( "I'll arbitrarily let angle A = 30°, angle B = 100°, and angle C = 50°\r\n" );
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document.write( "By the law of sines,\r\n" );
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document.write( "\"a%2Fsin%28%2230%B0%22%29=b%2Fsin%28%22100%B0%22%29\"\r\n" );
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document.write( "\"a%2Asin%28%22100%B0%22%29=b%2Asin%28%2230%B0%22%29\"\r\n" );
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document.write( "\"a=%28b%2Asin%28%2230%B0%22%29%29%2Fsin%28%22100%B0%22%29\"\r\n" );
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document.write( "\"c%2Fsin%28%2250%B0%22%29=b%2Fsin%28%22100%B0%22%29\"\r\n" );
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document.write( "\"c%2Asin%28%22100%B0%22%29=b%2Asin%28%2250%B0%22%29\"\r\n" );
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document.write( "\"c=%28b%2Asin%28%2250%B0%22%29%29%2Fsin%28%22100%B0%22%29\"\r\n" );
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document.write( "Perimeter = a + b + c = 20, so substituting in\r\n" );
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document.write( "\"a+%2B+b+%2B+c+=+20\",\r\n" );
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document.write( "\"a=%28b%2Asin%28%2230%B0%22%29%29%2Fsin%28%22100%B0%22%29\"\r\n" );
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document.write( "-----\r\n" );
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document.write( "\"c=%28b%2Asin%28%2250%B0%22%29%29%2Fsin%28%22100%B0%22%29\"\r\n" );
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document.write( "\"c=%28b%2Asin%28%2250%B0%22%29%29%2Fsin%28%22100%B0%22%29\"\r\n" );
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document.write( "Edwin

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