document.write( "Question 255269: A circle is inscribed in a given square and another circle is circumscribed about the same square. If the area of the circumscribed circle is 4, what is the area of the inscribed circle?\r
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Algebra.Com's Answer #187829 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
A circle is inscribed in a given square and another circle is circumscribed about the same square.
\n" ); document.write( " If the area of the circumscribed circle is 4, what is the area of the inscribed circle?
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\n" ); document.write( "Find the radius of the outer circle
\n" ); document.write( "\"pi%2Ar%5E2+=+4\"
\n" ); document.write( "\"r%5E2+=+4%2Fpi\"
\n" ); document.write( "r = \"sqrt%284%2Fpi%29\" is the radius of the large circle
\n" ); document.write( "then
\n" ); document.write( "diameter = \"2sqrt%284%2Fpi%29\"
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\n" ); document.write( "This is also the diagonal of the square
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\n" ); document.write( "Find the square dimensions using this as the diagonal(a^2 + b^2 = c^2)
\n" ); document.write( "Find the sides of the square. (s = the side of the square)
\n" ); document.write( "s^2 + s^2 = (\"2sqrt%284%2Fpi%29\")^2
\n" ); document.write( "2s^2 = 4(4/pi)
\n" ); document.write( "s^2 = 2(4/pi)
\n" ); document.write( "s^2 = 8/pi,
\n" ); document.write( "s = \"sqrt%288%2Fpi%29\"
\n" ); document.write( "s = \"2sqrt%282%2Fpi%29\" is the side of the square
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\n" ); document.write( "This is also the diameter of the small circles, therefore
\n" ); document.write( "r = \"sqrt%282%2Fpi%29\" (half the diameter)
\n" ); document.write( "r^2 = \"%282%2Fpi%29\"
\n" ); document.write( "Find the area of the small circle
\n" ); document.write( "A = \"pi+%2A+%282%2Fpi%29\"
\n" ); document.write( "A = 2 sq/cm; area of the small circle\r
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