document.write( "Question 255607: Two candles of equal length start burning at the same time. One will last 4 hours
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document.write( "and the other 6 hours. How many hours will they burn before one candle is twice
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document.write( "the length of the other? \n" );
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Algebra.Com's Answer #187821 by drk(1908)![]() ![]() ![]() You can put this solution on YOUR website! Put this into a chart: \n" ); document.write( "first . . . . .X . . . . .(3/4)X . . . . . (1/2)X . . . . (1/4)X . . . . 0X \n" ); document.write( "second . . .Y . . . .(5/6)Y . . . . . . (4/6)Y . . . .(3/6)Y . . . . (2/6)Y . . . .(1/6)Y . . . . 0Y \n" ); document.write( "time . . . . .0 . . . . .1 . . . . . . . . . .2 . . . . . . . . .3 . . . . . . . .. 4 . . . . . . . 5 . . . . . . .6\r \n" ); document.write( "\n" ); document.write( "Notice that 2*(1/4) = 1/2. This occurs at 3 hours. \n" ); document.write( " |