document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=32201>Question 32201</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Show that neither x=1 nor x=-1 cxan be solution to the equations ax^2+2bx+a=0 where a and b are integers with b odd. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #18780 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=18780\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> LET F(X)=AX^2+BX+A......NOT 2BX I THINK AS YOU CAN SEE BELOW....IF X=1 IS TO BE A SOLUTION THEN <BR>\n" );
document.write( "F(1)=A+B+A=2A+B=0.....NOW B IS ODD...IT CANT B EQUAL TO -2A WHICH IS AN EVEN NUMBER.<BR>\n" );
document.write( "SIMILARLY...F(-1)=A-B+A=2A-B=0.....NOW B IS ODD...IT CANT B EQUAL TO 2A WHICH IS AN EVEN NUMBER.<BR>\n" );
document.write( "HENCE X=1 OR -1 BE THE SOLUTION...<BR>\n" );
document.write( "YOU CAN SEE THAT THIS WILL NOT BE THE CASE IF IT IS 2B AND NOT B.  </SPAN>\n" );
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