document.write( "Question 255576: Car A starts in Sacramento at 11am. It travels along 400 mile route to LA at 50mph. Car B starts from Los Angeles at noon and travels to Sacramento along the same route at 75 mph. The route goes past Fresno which is 150 miles along the route from Los Angeles. How far from Fresno are the cars when they meet? \n" ); document.write( "
Algebra.Com's Answer #187795 by palanisamy(496)\"\" \"About 
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Let the cars meet at a time t after 12 noon.
\n" ); document.write( "The speed of car A = 50 mph
\n" ); document.write( "The distance travelled by A in(t+1)hours is x = 50(t+1)miles
\n" ); document.write( "The speed of car B = 75 mph
\n" ); document.write( "The distance travelled by B in t hours is y = 75t miles
\n" ); document.write( "But, x+y = 400 miles
\n" ); document.write( " 50(t+1)+75t = 400
\n" ); document.write( " 50t+50+75t = 400
\n" ); document.write( " 125t = 400-50
\n" ); document.write( " 125t = 350
\n" ); document.write( " t = 350/125
\n" ); document.write( " t = 2 100/125 hours
\n" ); document.write( " t = 2h 48 minutes
\n" ); document.write( "The distance travelled by B = 75t = 210 miles
\n" ); document.write( "But Fresno is 150 miles from LA
\n" ); document.write( "So the distance between the point of meeting and Fresno = 210-150 = 60 miles\r
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