document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=255422>Question 255422</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two angles are complementary. The sum of the measure of the first angle and one-forth the second angle is 64.5 degree. Find the measures of the angles.\r<BR>\n" );
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document.write( "What is the measure of the smaller angle?\r<BR>\n" );
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document.write( "What is the measure of the other angle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #187751 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=187751\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a+b=90<BR>\n" );
document.write( "a+b/4=64.5<BR>\n" );
document.write( "a=90-b<BR>\n" );
document.write( "a=64.5-b/4<BR>\n" );
document.write( "set the a's equal<BR>\n" );
document.write( "90-b=64.5-b/4<BR>\n" );
document.write( "35.5=3b/4<BR>\n" );
document.write( "142=3b<BR>\n" );
document.write( "142/3=b<BR>\n" );
document.write( "34=b smaller angle<BR>\n" );
document.write( "56=a larger angle<BR>\n" );
document.write( "check<BR>\n" );
document.write( "56+34/4=64.5<BR>\n" );
document.write( "34/4=8.5<BR>\n" );
document.write( "34=34\r<BR>\n" );
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document.write( " </SPAN>\n" );
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