document.write( "Question 255430: dave is three times older than Jim, and Jim is half Bill's age. If their average age is 64, what is Jim's age? \n" ); document.write( "

Algebra.Com's Answer #187677 by drk(1908) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let B = Bill, D = Dave, and J = JIm.
\n" ); document.write( "(i) $\"D+=+3J\"$
\n" ); document.write( "(ii) J = (1/2)B
\n" ); document.write( "(iii) $\"%28B+%2B+D+%2B+J%29%2F3+=+64\"$
\n" ); document.write( "From (ii)
\n" ); document.write( "(iv) B = 2J.
\n" ); document.write( "Subbing (i), (ii) and (iv) into (iii), we get
\n" ); document.write( "(v) $\"2J+%2B+3J+%2B+J+=+192\"$
\n" ); document.write( "(vi) $\"6J+=+192\"$
\n" ); document.write( "(vii) $\"J+=+32\"$
\n" ); document.write( "This means that B = 64 and D = 96.
\n" ); document.write( "Jim = 32. \n" ); document.write( "

\n" );