document.write( "Question 32242: the perimeter of a rectangle is 1100 feet. find the dimension so that the enclosed area will be 60,000 square feet. \n" ); document.write( "

Algebra.Com's Answer #18767 by Paul(988) $\"\"$ $\"About$

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THe formula for the perimeter is:
\n" ); document.write( "2(l+w)=P
\n" ); document.write( "In this case P = 1100 and length and width are unknown.
\n" ); document.write( "2l+2w=1100
\n" ); document.write( "Solve for length:
\n" ); document.write( "l=550-w (subsitution)
\n" ); document.write( "The Area in this case is A=60000
\n" ); document.write( "lw=60000
\n" ); document.write( "Subsitute for l
\n" ); document.write( "(550-w)(w)=60000
\n" ); document.write( " $\"-w%5E2%2B550w=60000\"$
\n" ); document.write( " $\"w%5E2-550w%2B60000=0\"$
\n" ); document.write( "Factor: (w-150) or (w-400)
\n" ); document.write( "Remvoe the 150 x=400
\n" ); document.write( "l=550-400
\n" ); document.write( "l=150
\n" ); document.write( "Hence, the width is 150ft and the length is 400ft.
\n" ); document.write( "Paul. \n" ); document.write( "

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