document.write( "Question 255374: The sum of the squares of two consecutive odd positive integers is 202. Find the integers. \n" ); document.write( "
Algebra.Com's Answer #187643 by drk(1908)\"\" \"About 
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let x = positive odd integer and x + 2 be the next positive odd integer.
\n" ); document.write( "we get
\n" ); document.write( "x^2 + (x+2)^2 = 202
\n" ); document.write( "foiling the left and combining like terms, we get
\n" ); document.write( "2x^2 + 4x + 4 = 202
\n" ); document.write( "and then
\n" ); document.write( "2x^2 + 4x - 198 = 0
\n" ); document.write( "divide by 2 to get
\n" ); document.write( "x^2 + 2x - 99 = 0
\n" ); document.write( "factor to get
\n" ); document.write( "(x+11)(x-9) = 0
\n" ); document.write( "solving for x, we get
\n" ); document.write( "x = -11 and x = 9
\n" ); document.write( "we get (-11,-9) OR (9,11)
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