document.write( "Question 255374: The sum of the squares of two consecutive odd positive integers is 202. Find the integers. \n" ); document.write( "
Algebra.Com's Answer #187643 by drk(1908)![]() ![]() ![]() You can put this solution on YOUR website! let x = positive odd integer and x + 2 be the next positive odd integer. \n" ); document.write( "we get \n" ); document.write( "x^2 + (x+2)^2 = 202 \n" ); document.write( "foiling the left and combining like terms, we get \n" ); document.write( "2x^2 + 4x + 4 = 202 \n" ); document.write( "and then \n" ); document.write( "2x^2 + 4x - 198 = 0 \n" ); document.write( "divide by 2 to get \n" ); document.write( "x^2 + 2x - 99 = 0 \n" ); document.write( "factor to get \n" ); document.write( "(x+11)(x-9) = 0 \n" ); document.write( "solving for x, we get \n" ); document.write( "x = -11 and x = 9 \n" ); document.write( "we get (-11,-9) OR (9,11) \n" ); document.write( " |