document.write( "Question 255357: The measure of the supplement of an angle exceeds three times the measure of half the compliment of the angle by 12. Find the measure of half the supplement \n" ); document.write( "

Algebra.Com's Answer #187625 by drk(1908) $\"\"$ $\"About$

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Let x be an angle.
\n" ); document.write( "180-x is the supplement.
\n" ); document.write( "90 - x is the compliment.
\n" ); document.write( "So, we get
\n" ); document.write( " $\"180-x+=+3%2A%281%2F2%29%2A%2890-x%29+%2B+12\"$
\n" ); document.write( "By distributive prperty, we get
\n" ); document.write( " $\"180-x+=+135+-+%283%2F2%29%29x+%2B+12\"$
\n" ); document.write( "combining like terms on the right we get
\n" ); document.write( " $\"180-x+=+147+-+%283%2F2%29x\"$
\n" ); document.write( "and simplifying we get
\n" ); document.write( " $\"33+=+%281%2F2%29x\"$
\n" ); document.write( " $\"66+=+x\"$
\n" ); document.write( "The supplement of 66 is 114. Half of 114 is 57.
\n" ); document.write( "So answer is 57. \n" ); document.write( "

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